判断Email是否有效

判断Email是否有效,返回1表示正确
Function isEmail(aEmail)
Dim iLocat,v,iLength,i,checkletter
If instr(aEmail,"@") = 0 Or instr(aEmail,".") = 0 Then
   isEmail=0
   EXIT FUNCTION
End If
iLocat=instr(aEmail,"@")
If instr(iLocat,aEmail,".")=0 Or instr(iLocat+1,aEmail,"@")>0 Then
   isEmail=0
   EXIT FUNCTION
End If
If left(aEmail,1)="." Or right(aEmail,1)="." Or left(aEmail,1)="@" Or right(aEmail,1)="@" Then
   isEmail=0
   EXIT FUNCTION
End If
v="1234567890abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ_-.@"
iLength=len(aEmail)
For i=1 To iLength
   checkletter=mid(aEmail,i,1)
   If instr(v,checkletter)=0 Then
    isEmail=0
    EXIT FUNCTION
   End If
Next
isEmail=1
End Function